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Trigonometry – II — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsTrigonometry – II2 Marks
MCQ
$\sin ^2 17.5^{\circ}+\sin ^2 72.5^{\circ}$ is equal to
  • A
    $\cos ^2 90^{\circ}$
  • ✓
    $\tan ^2 45^{\circ}$
  • C
    $\cos ^2 30^{\circ}$
  • D
    $\sin ^2 45^{\circ}$
✓

Answer

Correct option: B.
$\tan ^2 45^{\circ}$
(B)
$\sin ^2 17.5^{\circ}+\sin ^2 72.5^{\circ}$
$=\sin ^2 17.5^{\circ}+\left[\sin \left(90^{\circ}-17.5^{\circ}\right)\right]^2$
$=\sin ^2 17.5^{\circ}+\cos ^2 17.5^{\circ}$
$=1=\tan ^2 45^{\circ}$

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