Question
$\sin 50^\circ - \sin 70^\circ + \sin 10^\circ = $

Answer

b
(b) $\sin \,\,{50^o} - \sin \,\,{70^o} + \sin \,\,{10^o}$

$ = - 2\,\,\cos \,\,{60^o}\sin \,\,{10^o} + \sin \,\,{10^o}$

$ = \,\sin \,{10^o}\,(1 - 2\,\,\cos \,\,{60^o}) = 0.$

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