75^ =? - Vidyadip

MCQ

$\sin 75^{\circ}=?$

A
$\frac{(\sqrt{2}-1)}{2 \sqrt{2}}$
B
$\frac{(\sqrt{3}-1)}{2 \sqrt{2}}$
C
$\frac{(\sqrt{3}+1)}{2 \sqrt{2}}$
D
$\frac{(\sqrt{2}+1)}{2 \sqrt{2}}$

✓

Answer

(c) $\frac{(\sqrt{ } 1+1)}{2 \sqrt{2}}$
Explanatien: $\sin 75^{\circ}=\sin \left(90^{\circ}-15^{\circ}\right)=\cos 15^{\circ}=\frac{(\sqrt{3}+1)}{2 \sqrt{2}}$

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