MCQ
$\sin \,\left[ {{{\cos }^{ - 1}}\left( {\frac{3}{5}} \right) + {{\tan }^{ - 1}}2} \right]$ =
- ✓$\frac{2}{{\sqrt 5 }}$
- B$\frac{-2}{{\sqrt 5 }}$
- C$\frac{3}{{\sqrt 5 }}$
- D$\frac{-3}{{\sqrt 5 }}$
$=\sin \left[\sin ^{-1}\left(\frac{4}{5} \sqrt{1-\frac{4}{5}}+\frac{2}{\sqrt{5}}\right)\right]$
$=\sin \left[\sin ^{-1}\left(\frac{10}{5 \sqrt{5}}\right)\right]$
$=\frac{2}{\sqrt{5}}$
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| $X$ | 2 | 3 | 4 | 5 |
| $P(X)$ | $\frac{5}{k}$ | $\frac{7}{k}$ | $\frac{9}{k}$ | $\frac{11}{k}$ |