MCQ
$\sin^230^\circ+4\cot^245^\circ-\sec^260^\circ=?$
- A$0$
- ✓$\frac{1}{4}$
- C$4$
- D$1$
$\sin^230^\circ+4\cot^245^\circ-\sec^260^\circ$
$=\Big(\frac{1}{2}\Big)^2+4(1)^2-(2)^2$
$=\frac{1}{4}+4-4$
$=\frac{1}4{}$
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