Download App

Trigonometric Ratios Of Compounds — MATHS STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceMATHSTrigonometric Ratios Of Compounds1 Mark
MCQ
$\frac{\sin3\text{x}}{1+2\cos2\text{x}}$ is equal to:
  • A
    $\cos\text{x}$
  • ✓
    $\sin\text{x}$
  • C
    $-\cos\text{x}$
  • D
    $\sin\text{x}$
✓

Answer

Correct option: B.
$\sin\text{x}$
We have,
$\frac{\sin3\text{x}}{1+2\cos2\text{x}}=\frac{3\sin\text{x}-4\sin^2\text{x}}{1+2(1-2\sin^2\text{x})}$
$=\frac{3\sin\text{x}-4\sin^3\text{x}}{1+2-4\sin\text{x}}$
$=\frac{\sin\text{x}(3-4\sin^2\text{x})}{(3-4\sin^2\text{x})}$
$=\sin\text{x}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Trigonometric Ratios Of Compounds→Trigonometric Ratios Of Compounds — all question types→MATHS STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The equations $x = \frac{t}{4},\;y = \frac{{{t^2}}}{4}$ represents
→
Let $p , q \in R$ and $(1-\sqrt{3} i )^{200}=2^{199}( p + iq )$, $i =\sqrt{-1}$ Then $p + q + q ^2$ and $p - q + q ^2$ are roots of the equation.
→
The shortest distance of the point $(0,0)$ from the curve $y = (e^x + e^{-x})$ is-
→
The number of way to sit $3$ men and $2 $ women in a bus such that total number of sitted men and women on each side is $3$
→
A and B are two events such that P (A) = 0.25 and P (B) = 0.50. The probability of both happening together is 0.14. The probability of both A and B not happening is
→
If ${(1 + x)^{15}} = {C_0} + {C_1}x + {C_2}{x^2} + ...... + {C_{15}}{x^{15}},$ then ${C_2} + 2{C_3} + 3{C_4} + .... + 14{C_{15}} = $
→
The diagonals of a parallelogram $PQRS$ are along the lines $x + 3y = 4$ and $6x - 2y = 7$. Then $PQRS$ must be a
→
If the set A has 3 elements and the set B = {1, 3, 4, 5}, then the number of elements in (A × B) is:
→
The domain of the function $y = \frac{1}{{\sqrt {|x|\; - x} }}$ is
→
The points $\left( {\frac{a}{{\sqrt 3 }},a} \right),\;\left( {\frac{{2a}}{{\sqrt 3 }},\,2a} \right),\;\left( {\frac{a}{{\sqrt 3 }},\,3a} \right)$ are the vertices of
→