MCQ
$\sin(45^\circ+\theta)-\cos(45^\circ-\theta)=?$
- A$2\sin\theta$
- B$2\cos\theta$
- ✓$0$
- D$1$
✓
Answer
Correct option: C.
$0$
$\sin(45^\circ+\theta)-\cos(45^\circ-\theta)$
$=\sin(45^\circ+\theta)-\cos[90^\circ-(45^\circ+\theta)]$
$=\sin(45^\circ+\theta)-\sin(45^\circ+\theta)$
$=0$
$=\sin(45^\circ+\theta)-\cos[90^\circ-(45^\circ+\theta)]$
$=\sin(45^\circ+\theta)-\sin(45^\circ+\theta)$
$=0$
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