MCQ
$\sin47^\circ\cos43^\circ+\cos47^\circ\sin43^\circ=?$
- A$\sin4^\circ$
- B$\cos4^\circ$
- ✓$1$
- D$0$
✓
Answer
Correct option: C.
$1$
$\sin47^\circ\cos43^\circ+\cos47^\circ\sin43^\circ$
$=\sin47^\circ\cos(90^\circ-47^\circ)+\cos47^\circ\sin(90^\circ-47^\circ)$
$=\sin47^\circ\sin47^\circ+\cos47^\circ\cos47^\circ$
$=\sin^247^\circ+\cos^247^\circ$
$=1$
$=\sin47^\circ\cos(90^\circ-47^\circ)+\cos47^\circ\sin(90^\circ-47^\circ)$
$=\sin47^\circ\sin47^\circ+\cos47^\circ\cos47^\circ$
$=\sin^247^\circ+\cos^247^\circ$
$=1$
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