MCQ
∫sin(log x) . dx =
  • $\frac{x}{2}[\sin (\log x)-\cos (\log x)]+c$
  • B
    $\frac{x}{2}[\sin (\log x)+\cos (\log x)]+c$
  • C
    $\frac{x}{2}[\cos (\log x)-\sin (\log x)]+c$
  • D
    $\frac{x}{4}[\cos (\log x)-\sin (\log x)]+c$

Answer

Correct option: A.
$\frac{x}{2}[\sin (\log x)-\cos (\log x)]+c$
$\frac{x}{2}[\sin (\log x)-\cos (\log x)]+c$

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