MCQ
Six dice are thrown. The probability that different numbers will turn up is equal to
  • A
    $\frac{5}{36}$
  • $\frac{5}{324}$
  • C
    $\frac{3}{324}$
  • D
    $\frac{1}{324}$

Answer

Correct option: B.
$\frac{5}{324}$
(B)
When six dice are thrown, the total number of outcomes is $6^6$. They can show different number in ${ }^6 P _6=6$ ! ways
$\therefore \quad$ Required probability $=\frac{6!}{6^6}=\frac{5!}{6^5}=\frac{5}{324}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free