Question
Sketch the graphs of the following function: $\text{h(x)}=2\sin3\text{x},0\leq\text{x}\leq\frac{2\pi}{3}$

Answer

$\text{h(x)}=2\sin3\text{x},0\leq\text{x}\leq\frac{2\pi}{3}$
$\text{x}$ $0$ $\frac{\pi}{3}$ $\frac{2\pi}{3}$
$\text{h(x)}=2\sin3\text{x}$ $0$ $0$ $0$

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