Question
Sketch the graphs of the following function: $\text{u(x)}=\sin^2\text{x},0\leq\text{x}\leq2\pi$ $\text{v(x)}=|\sin\text{x}|,0\leq\text{x}\leq2\pi$
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Answer
$\text{u(x)}=\sin^2\text{x},0\leq\text{x}\leq2\pi$ $\text{v(x)}=|\sin\text{x}|,0\leq\text{x}\leq2\pi$
| $\text{x}$ | $0$ | $\pi$ |
| $\text{u(x)}=\sin^2\text{x}$ | $0$ | $0$ |
| $\text{x}$ | $0$ | $\pi$ |
| $\text{v(x)}=|\sin\text{x}|$ | $0$ | $0$ |
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