Question
Sketch the graphs of the following function:
$\text{u(x)}=\sin^2\text{x},0\leq\text{x}\leq2\pi$
$\text{v(x)}=|\sin\text{x}|,0\leq\text{x}\leq2\pi$

Answer

$\text{u(x)}=\sin^2\text{x},0\leq\text{x}\leq2\pi$ $\text{v(x)}=|\sin\text{x}|,0\leq\text{x}\leq2\pi$
$\text{x}$ $0$ $\pi$
$\text{u(x)}=\sin^2\text{x}$ $0$ $0$
$\text{x}$ $0$ $\pi$
$\text{v(x)}=|\sin\text{x}|$ $0$ $0$

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