MCQ
સમીકરણ ${(a + b)^2} = 4ab\,\,{\sin ^2}\theta $ તોજ શક્ય છે જો . . . .
- A$2a = b$
- ✓$a = b$
- C$a = 2b$
- Dએકપણ નહી
$ \Rightarrow {\sin ^2}\theta = \frac{{{{(a + b)}^2}}}{{4ab}} \le 1 $
$\Rightarrow {(a + b)^2} - 4ab \le 0$
$ \Rightarrow {(a - b)^2} \le 0 $
$\Rightarrow a = b.$
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