Question
समीकरण $\frac{{dy}}{{dx}} = \frac{{{y^2} - y - 2}}{{{x^2} + 2x - 3}}$ का हल है
==> $\int_{}^{} {\frac{{dy}}{{(y - 2)(y + 1)}}} = \int_{}^{} {\frac{{dx}}{{(x + 3)(x - 1)}}} $
==> $\frac{1}{3}\int_{}^{} {\left( {\frac{1}{{y - 2}} - \frac{1}{{y + 1}}} \right)} dy = \frac{1}{4}\int_{}^{} {\left( {\frac{1}{{x - 1}} - \frac{1}{{x + 3}}} \right)\,} dx$
==> $\frac{1}{3}\log \left| {\frac{{y - 2}}{{y + 1}}} \right| = \frac{1}{4}\log \,\left| {\frac{{x - 1}}{{x + 3}}} \right| + c$.
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