S N^1 reaction is faster in - Vidyadip

MCQ

$S{N^1}$ reaction is faster in

A
$C{{H}_{3}}C{{H}_{2}}Cl$
B
✓
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,|} \\
{C{H_3} - C - Cl} \\
{\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
D
$C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{\underset{|}{\mathop{C}}\,{{H}_{2}}}{\mathop{\underset{|}{\mathop{C}}\,H\ }}\,}}\,-Cl$

✓

Answer

Correct option: C.

$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,|} \\
{C{H_3} - C - Cl} \\
{\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$

c
(c) $S{N^1}$ mechanism proceeds through carbocation intermediate.

$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,|} \\
{C{H_3} - C - Cl} \\
{\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$

provides stable carbocation intermediate because it has tertiary carbon.

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