MCQ
Sodium benzoate on heating with sodalime gives:
- ✓Benzene
- BBenzophenone
- CMethane
- DCalcium benzoate
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Reason : Oxidation takes place at anode and reduction at cathode.
${\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+},}$
${\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}}$
$A.$ $Sm ^{2+}$ $B.$ $Ce ^{2+}$ $C.$ $Ce ^{4+}$ $D.$ $Tb ^{4+}$
Choose the most appropriate answer from the options given below :