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STD 11 - 9. Hydricarbon — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 9. Hydricarbon4 Marks
MCQ
Sodium ethoxide is a specific reagent for
  • A
    Dehydration
  • B
    Dehydrogenation
  • ✓
    Dehydrohalogenation
  • D
    Dehalogenation
✓

Answer

Correct option: C.
Dehydrohalogenation
c
(c) $C{H_3} - C{H_2} - C{H_2} - Br\mathop {}\limits_{{\rm{}}} $ $  \xrightarrow[C_2H_5ONa]{Dehydro halogenati on }  $ $C{H_3} - CH = C{H_2} + HBr$

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