Question
Sodium forms a crystalline ionic solid with dihydrogen. The solid is non-volatile and non-conducting in nature. It reacts violently with water to produce dihydrogen gas. Write the formula of this compound and its reaction with water. What will happen on electrolysis of the melt of this solid?

Answer

The compound is NaH (sodium hydride)
$2\text{Na}+\text{H}_2\xrightarrow{\ \ \ \ \ \ \ \ \ }2\text{NaH} $
$\text{NaH}+\text{H}_2\text{O}\xrightarrow{\ \ \ \ \ \ \ \ }\text{NaOH}+\text{H}_2\text{(g)}$
When molten sodium hydride is electrolysed, Na will be formed at cathode and dihydrogen will be liberated at anode.
$2\text{NaH}\xrightarrow{\text{electrolysis}}2\text{Na}\ \ \ +\ \ \ \ \ \text{H}_2(\text{g})\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{At cathode}\ \ \ \ \ \ \ \ \ ^\text{At anode}$

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