MCQ
Solid $Ba(NO_3)_2$ is gradually dissolved in $1\times10^{-4}\, M\, Na_2CO_3$ solution. At what concentration of $Ba^{+2}$ the precipitation of $BaCO_3$ will start? (If $K_{sp}$ of $BaCO_3 = 5.1\times10^{-9}$)
  • A
    $4.1\times10^{-5}\, M$
  • $5.1\times10^{-5}\, M$
  • C
    $1.6\times10^{-4}\, M$
  • D
    $8.1\times10^{-7}\, M$

Answer

Correct option: B.
$5.1\times10^{-5}\, M$
b
$\left[\mathrm{Ba}^{+2}\right]\left(10^{-4}\right)=5.1 \times 10^{-9}$

$\boxed{\left[ {{\text{B}}{{\text{a}}^{ + 2}}} \right] = 5.1 \times {{10}^{ - 5}}{\mkern 1mu} {\text{M}}}$

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