MCQ
Solubility product of $BaC{l_2}$ is $4 \times {10^{ - 9}}$. Its solubility in moles/litre would be
- ✓$1 \times {10^{ - 3}}$
- B$1 \times {10^{ - 9}}$
- C$4 \times {10^{ - 27}}$
- D$1 \times {10^{ - 27}}$
✓
Answer
Correct option: A.
$1 \times {10^{ - 3}}$
(a) ${K_{sp}} = 4{S^3},$
${S^3} = \frac{{4 \times {{10}^{ - 9}}}}{4} = {10^{ - 9}}$
$\therefore \,S = {10^{ - 3}}M$.
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