MCQ
Solubility product of silver bromide is $5.0 \,\,\times \,\,10^{-13}$ . The quantity of potassium
bromide (molar mass taken as $120\,\,g\,mol^{-1}$ ) to be added to $1\,L$ of $0.05\,\,M$ solution of silver nitrate to start the precipitation of $AgBr$ is
bromide (molar mass taken as $120\,\,g\,mol^{-1}$ ) to be added to $1\,L$ of $0.05\,\,M$ solution of silver nitrate to start the precipitation of $AgBr$ is
- A$1.2\, \times \,{10^{ - 10}}\,g$
- ✓$1.2\, \times \,{10^{ - 9}}\,g$
- C$6.2\, \times \,{10^{ - 5}}\,g$
- D$5.0\, \times \,{10^{ - 8}}\,g$
