MCQ
Solution of $\int \sin 3 x d x$ is
  • A
    $\frac{1}{3} \cos 3 x+c$
  • B
    $\frac{1}{3} \sin 3 x+c$
  • C
    $-\frac{1}{3} \sin 3 x+c$
  • D
    $-\cos 3 x+c$

Answer

self

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