Solution of (x-1) 2 (x+4)<0 is: - Vidyadip

MCQ

Solution of $(\text{x}-1) 2 (\text{x}+4)<0$ is:

A
$(-\infty, 1)$
✓
$(\infty, –4)$
C
$(– 1, 4)$
D
$(1, 4)$

✓

Answer

Correct option: B.

$(\infty, –4)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Linear Inequalities→Linear Inequalities — all question types→Maths STD 11 Science question papers→CBSE Board STD 11 Science question papers→CBSE Board question paper generator→

Similar questions

The ratio in which the line joining the points $(a, b, c)$ and $(-a, -c, -b)$ is divided by the $xy-$plane is

If $|z|\, = 1$ and $\omega = \frac{{z - 1}}{{z + 1}}$ (where $z \ne - 1)$, then ${\mathop{\rm Re}\nolimits} (\omega )$ is

Let $\omega \neq 1$ be a cube root of unity. Then the minimum of the set

$\left\{\left| a + b \omega+ c \omega^2\right|^2: a , b , c \text { distinct non-zero integers }\right\}$ equals. . . . .

From any point on the circle ${x^2} + {y^2} = {a^2}$ tangents are drawn to the circle ${x^2} + {y^2} = {a^2}{\sin ^2}\alpha $, the angle between them is

The locus of a point which divides the join of $A( - 1,\;1)$ and a variable point $P$ on the circle ${x^2} + {y^2} = 4$ in the ratio $3 : 2$, is

A polygon has $35$ diagonals, then the number of its sides is

If the line $ax + y = c,$ touches both the curves $x^2 + y^2 = 1$ and $y^2 - 4\sqrt 2 x ,$ then $|c|$ is equal to

If $ \mathrm{f}(\mathrm{x})=\left\{\begin{array}{l}2\mathrm{x}+\mathrm{b}(\mathrm{x}<\alpha)\\\mathrm{x}+\mathrm{d}(\mathrm{\text{x}}\geq\alpha)\end{array}\right.$ is such that $ \lim_\limits{\text{x} \rightarrow \text{a}}\text{f}(\text{x}=\text{L}),$ then $L.$

$\cos 40^{\circ}+\cos 80^{\circ}+\cos 160^{\circ}+\cos 240^{\circ}=$

The product of three consecutive natural numbers is divisible by: