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STD 12 - 9. differential equations — Mathematics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceMathematicsSTD 12 - 9. differential equations1 Mark
MCQ
Solution of the differential equation, $\frac{{dy}}{{dx}} = \frac{{1 - 2y - 4x}}{{1 + y + 2x}}$ is
  • ✓
    $4x^2 + 4xy + y^2 - 2x 2y + c = 0$
  • B
    $4x^2 - 4xy -y^2 - 2x - 2y + c = 0$
  • C
    $4x^2 + 4xy + y^2 2x 2y + c = 0$
  • D
    $4x^2 + 4xy -y^2 - 2x 2y + c = 0$
✓

Answer

Correct option: A.
$4x^2 + 4xy + y^2 - 2x 2y + c = 0$
a
Note that $\frac{{dy}}{{dx}}\,\, = \,\,\frac{{ - 4x\, - \,2y + 1}}{{2x + y + 1}}\,\,;\,({b_1}\, + {a_2}\, = \,0)\,$
$\Rightarrow$ simplify cross multiply

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