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STD 11 - basic of algoritham — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - basic of algoritham4 Marks
MCQ
Solution of the equation  ${4.9^{x - 1}} = 3\sqrt {({2^{2x + 1}})} $ has the solution
  • A
    $3$
  • B
    $2$
  • ✓
    $1.5$
  • D
    $2/3$
✓

Answer

Correct option: C.
$1.5$
c
(c) $4.\,{9^{x - 1}} = 3\,.\,\sqrt {({2^{2x + 1}})} $$ \Rightarrow $${3^{2x - 2 - 1}} = {2^{{{2x + 1} \over 2} - 2}}$

$ \Rightarrow $ ${3^{2x - 3}} = {2^{{{2x - 3} \over 2}}}$ $ \Rightarrow $ ${2^{{{2x - 3} \over 2}}} = {\left( {{3^{{{2x - 3} \over 2}}}} \right)^2}$
 $ \Rightarrow $$2x - 3 = 0$,

$\therefore x = {3 \over 2}$.

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