MCQ
Solution of the equation ${4.9^{x - 1}} = 3\sqrt {({2^{2x + 1}})} $ has the solution
- A$3$
- B$2$
- ✓$1.5$
- D$2/3$
✓
Answer
Correct option: C.
$1.5$
c
(c) $4.\,{9^{x - 1}} = 3\,.\,\sqrt {({2^{2x + 1}})} $$ \Rightarrow $${3^{2x - 2 - 1}} = {2^{{{2x + 1} \over 2} - 2}}$
(c) $4.\,{9^{x - 1}} = 3\,.\,\sqrt {({2^{2x + 1}})} $$ \Rightarrow $${3^{2x - 2 - 1}} = {2^{{{2x + 1} \over 2} - 2}}$
$ \Rightarrow $ ${3^{2x - 3}} = {2^{{{2x - 3} \over 2}}}$ $ \Rightarrow $ ${2^{{{2x - 3} \over 2}}} = {\left( {{3^{{{2x - 3} \over 2}}}} \right)^2}$
$ \Rightarrow $$2x - 3 = 0$,
$\therefore x = {3 \over 2}$.
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