Question
Solve: $\frac{15(2-\text{y})-5(\text{y}+6)}{1-3\text{y}}=10$
✓
Answer
$\frac{15(2-\text{y})-5(\text{y}+6)}{1-3\text{y}}=10$ $\Rightarrow\frac{30 - 15\text{y} - 5\text{y} - 30}{1 - 3\text{y}} = 10$ $\Rightarrow \frac{-20\text{y}}{1 - 3\text{y}} = 10$ $\Rightarrow1 (-20\text{y}) = 10 (1 - 3\text{y})$ (by cross multiplication) $\Rightarrow-20\text{y} = 10 - 30\text{y}$ $\Rightarrow-20\text{y} + 30\text{y} = 10$ $\Rightarrow10\text{y} = 10$ $\Rightarrow\text{y} = \frac{10}{10} = 1$ $\therefore\text{y} = 1$
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