Question
Solve: $2 cos^2 x + 3$ sin $x = 0$

Answer

$2 cos^2 x + 3 sin x = 0$
$\Rightarrow$ $2 (1 - sin^2 x) + 3 sin x = 0$
$\Rightarrow$ $2 sin^2 x - 3 sinx - 2 = 0$
$\Rightarrow$ $2 sin^2\ x - 4 sin\ x + sin\ x - 2 = 0$
$\Rightarrow$ 2 sin x (sin x - 2) +1 (sin x - 2 ) = 0
$\Rightarrow$ (sin x - 2) (2 sin x +1) = 0
$\Rightarrow$ 2sin x + 1 = 0 $[\because \sin x \neq 2 \quad \therefore \sin x-2 \neq 0]$
$\Rightarrow \quad \sin x=-\frac{1}{2}$
$\Rightarrow \quad \sin x=\sin \left(-\frac{\pi}{6}\right) \Rightarrow x=n \pi+(-1)^{n}\left(-\frac{\pi}{6}\right), n \in Z \Rightarrow x=n \pi+$$(-1)^{n+1} \frac{\pi}{6}, \quad n \in Z.$

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