Solve: 2x+1>3 - Vidyadip

MCQ

Solve: $2\text{x}+1>3$

A
$\big[1,1\big)$
✓
$\big(1,\infty\big)$
C
$\big(\infty,\infty\big)$
D
$\big(\infty, 1\big)$

✓

Answer

Correct option: B.

$\big(1,\infty\big)$

Given, $2\text{x}+1>3$
$\Rightarrow2\text{x}>3-1$
$\Rightarrow2\text{x}>2$
$\Rightarrow\text{x}>1$
$\Rightarrow\text{x}\in\big(1,\infty\big)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from LINEAR INEQUALITIES→LINEAR INEQUALITIES — all question types→MATHS STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The locus of feet of perpendicular from either foci of the ellipse

$(x - y +1)^2 + (2x + 2y - 6)^2 = 20$ on any tangent will be

If $\cos^4 \theta +\alpha, \sin^4 \theta + \alpha$ are the roots of the equation $x^2+2bx + b = 0$ and $\cos^2 \theta + \beta, \sin^2 \theta + \beta$ are the roots of the equation $x^2+4x+2 = 0$ then find $b$ ?

The points (-5, 12), (-2, -3), (9, -10), (6, 5) taken in order, form:

When $\frac{{z + i}}{{z + 2}}$ is purely imaginary, the locus described by the point $z$ in the Argand diagram is a

Let $f(x)=\int_0^x\left(t+\sin \left(1-e^t\right)\right) d t, x \in \mathbb{R}$. Then $\lim _{x \rightarrow 0} \frac{f(x)}{x^3}$ is equal to

The arithmetic mean of the nine numbers in the given set $\{9,99,999,...., 999999999\}$ is a $9$ digit number $N$, all whose digits are distinct. The number $N$ does not contain the digit

If n(A) = 65, n(B) = 32 and n(A ∩ B) = 14, then n(A Δ B) equals:

The equation of a circle passing through points of intersection of the circles ${x^2} + {y^2} + 13x - 3y = 0$ and $2{x^2} + 2{y^2} + 4x - 7y - 25 = 0$ and point $(1, 1)$ is

$\mathop {\lim }\limits_{x \to 1} {\left( {\frac{4}{\pi }{{\tan }^{ - 1}}x} \right)^{\frac{1}{{({x^2} - 1)}}}}$ is equal to -

In set-builder method the null set is represented by:

$\{\}$
$\phi$
$\{\text{x : x} \not=\text{x}\}$
$\{\text{x : x} =\text{x}\}.$