MCQ
Solve $(2x + 3)^2 + (2x - 3)^2 = (8x + 6) (x - 1) + 22$
  • $-1$
  • B
    $-2$
  • C
    $-3$
  • D
    $-4$

Answer

Correct option: A.
$-1$
$(2x + 3)^2 + (2x - 3)^2 = (8x + 6) (x - 1) + 22$
$\Rightarrow 4x^2+ 12x + 9 + 4x^2 - 12x + 9 = 8x^2 - 8x + 6x - 6 + 22$
$\Rightarrow 8x^2 + 18 = 8x^2 - 2x + 16$
$\Rightarrow 2x = -2$
$\Rightarrow\text{x}=\frac{-2}{2} \therefore \text{x}=-1$

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