MCQ
Solve: $3 x+5< x-7$, when $x$ is a real number
- A$x>-12$
- B$x<-12$
- C$x<-6$
- D$x>-6$
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If $\text{y}=\frac{\sin(\text{x}+9)}{\cos\text{x}}$ then $\frac{\text{dy}}{\text{dx}}$ at x = 0 is equal to:
$\cos9$
$\sin9$
$0$
$1$