Solve: 3x + 8 >2, when x is an integer. - Vidyadip

Question

Solve: 3x + 8 >2, when x is an integer.

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Answer

It is given in the question that,
3x + 8 > 2
$\Rightarrow$ 3x + 8 – 8 >2 – 8
$\Rightarrow$ 3x >- 6
$\Rightarrow$ $\frac{3 x}{3}>\frac{-6}{3}$
$\Rightarrow$ x > -2, where x is an integer
It can be clearly observed that the integer number greater than -2 are -1, 0, 1, 2,...
Thus, solution of 3x + 8 > 2 is -1, 0, 1, 2,… when x is an integer.
$\therefore$ solution set = {-1, 0, 1, 2,…}

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