Question
Solve: $\frac{4\text{x}+7}{9-3\text{x}}=\frac{1}{4}$
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Answer
$\frac{4\text{x}+7}{9-3\text{x}}=\frac{1}{4}$ $\Rightarrow4(4\text{x}+7)=1(9-3\text{x})$ (by cross multiplication) $\Rightarrow16\text{x}+28=9-3\text{x}$ $\Rightarrow16\text{x}+3\text{x}=9-28$ $\Rightarrow19\text{x}=-19$ $\Rightarrow\text{x}=\frac{-19}{19}=1$ $\therefore\text{x}=-1$
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