Question
Solve :$5 x+\frac{8}{y}=19, 3 x-\frac{4}{y}=7$
✓
Answer
$5 x+\frac{8}{y}=19\ldots .(1)$
$3 x-\frac{4}{y}=7\ldots . .(2)$
Multiplying equation $(2)$ by $2$ , We get,
$6 x-\frac{8}{y}=14 \dots......(3)$
Adding $(1)$ and $(3)$, We get,
$\begin{gathered}5 x+\frac{8}{y}=19,+6 x-\frac{8}{y}=14,11 x=33,x=3\end{gathered}$
Substituting $x=3$ in equation $(1),$ We get
$5(3)+\frac{8}{y}=19$
$ 15+\frac{8}{y}=19$
$ \frac{8}{y}=19-15$
$ y=\frac{8}{4}$
$ y=2$
$3 x-\frac{4}{y}=7\ldots . .(2)$
Multiplying equation $(2)$ by $2$ , We get,
$6 x-\frac{8}{y}=14 \dots......(3)$
Adding $(1)$ and $(3)$, We get,
$\begin{gathered}5 x+\frac{8}{y}=19,+6 x-\frac{8}{y}=14,11 x=33,x=3\end{gathered}$
Substituting $x=3$ in equation $(1),$ We get
$5(3)+\frac{8}{y}=19$
$ 15+\frac{8}{y}=19$
$ \frac{8}{y}=19-15$
$ y=\frac{8}{4}$
$ y=2$
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