Question
Solve: $\frac{6 x+1}{3}+1=\frac{x-3}{6}$
✓
Answer
$\frac{6 x+1}{3}+1=\frac{x-3}{6}$
Multiplying both sides of the equation by $6,$
$\frac{6(6 x+1)}{3}+6 \times 1=\frac{6(x-3)}{6}$
or $2(6x + 1) + 6 = x - 3$
or $12x + 2 + 6 = x - 3$
or $12x + 8 = x - 3$
or $12x – x = -3 -8$
or $11x = -11$
or $x = -1$
Multiplying both sides of the equation by $6,$
$\frac{6(6 x+1)}{3}+6 \times 1=\frac{6(x-3)}{6}$
or $2(6x + 1) + 6 = x - 3$
or $12x + 2 + 6 = x - 3$
or $12x + 8 = x - 3$
or $12x – x = -3 -8$
or $11x = -11$
or $x = -1$
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