Question
Solve:
$96-4 x-x^2$
$96-4 x-x^2$
✓
Answer
$96-4 x-x^2$
$=100-4-4 x-x^2$
$=100-\left(x^2+4 x+4\right)$
$=100-\left(x^2+2 \times x \times 2+2^2\right)$
$=10^2-(x+2)^2$
$=[10-(x+2)][10+(x+2)]$
$=(10-x-2)(10+x+2)$
$=(8-x)(12+x)$
$=(x+12)(-x+8)$
$=100-4-4 x-x^2$
$=100-\left(x^2+4 x+4\right)$
$=100-\left(x^2+2 \times x \times 2+2^2\right)$
$=10^2-(x+2)^2$
$=[10-(x+2)][10+(x+2)]$
$=(10-x-2)(10+x+2)$
$=(8-x)(12+x)$
$=(x+12)(-x+8)$
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