Question
Solve and graph the solution set of $:x + 5 ≥ 4(x - 1)$ and $3 - 2x < -7 ; x \in R .$

Answer

$x+5 \geq 4(x-1)$ and $3-2 x<-7$
$9 \geq 3 x \text { and }-2 x<-10$
$ 3 \geq x \text { and } x>5$
$\therefore$ Solution set = Empty set

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