Solve Cryptarithms. 1 2 A + 6 A B A 0 9 - Vidyadip

Question

Solve Cryptarithms. $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1\ \ \ \ 2 \ \ \ \ \text{A}\ \ \ \ \ \ \ \\ \ \ \ \ \ \ \ \ \ \ \underline{+\ \ \ \ 6\ \ \ \ \text{A}\ \ \ \ \text{B}\ \ }\\\ \ \ \ \ {\ \ \ \ \ \ \ \ \ \ \ \ \ \text{A}\ \ \ \ 0\ \ \ \ \ 9}$

✓

Answer

$A + B = 9$ as the sum of two digits can never be $192 + A = 0, A$ must be $8A + 9, 8 + B = 9, B = 1$ So, $A = 8, B = 1$

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