Solve Cryptarithms. 1 2 A + 6 A B A 0 9 - Vidyadip

Question

Solve Cryptarithms.
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1\ \ \ \ 2 \ \ \ \ \text{A}\ \ \ \ \ \ \ \\ \ \ \ \ \ \ \ \ \ \ \underline{+\ \ \ \ 6\ \ \ \ \text{A}\ \ \ \ \text{B}\ \ }\\\ \ \ \ \ {\ \ \ \ \ \ \ \ \ \ \ \ \ \text{A}\ \ \ \ 0\ \ \ \ \ 9}$

✓

Answer

A + B = 9 as the sum of two digits can never be 192 + A = 0, A must be 8A + 9, 8 + B = 9, B = 1
So, A = 8, B = 1

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