Differential Equation and Applications (p-1) — Maths (commerce) STD 12 Commerce / Arts — Question
Maharashtra BoardEnglish MediumSTD 12 Commerce / ArtsMaths (commerce)Differential Equation and Applications (p-1)2 Marks
Question
Solve $\frac{d y}{d x}=\log xdx$
✓
Answer
$ \begin{aligned} & \frac{d y}{d x}=\log xdx \\ & \therefore d y =\log xdx \end{aligned} $ On integrating, we get $ \begin{aligned} & \int dy =\int \log x \cdot 1 dx \\ & \therefore y =(\log x ) \int 1 dx -\int\left[\left\{\frac{d}{d x}(\log x)\right\} \cdot \int 1 d x\right] d x \\ & \therefore y =(\log x ) \cdot x -\int \frac{1}{x} \cdot x d x \\ & \therefore y = x \log x -\int 1 dx \\ & \therefore y = x \log x - x + c \end{aligned} $ This is the general solution.
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