Question
Solve each of the following equations using the formula:
$x^2+6 x-10=0$
$x^2+6 x-10=0$
✓
Answer
$x^2+6 x-10=0$
Here a = 1, b = 6 and c = – 10
Then $x =-\frac{b \pm \sqrt{b}^2-4 a c}{2 a}$
$=\frac{-(6) \pm \sqrt{(-6)^2-4(1)(-10)}}{2(1)}$
$=\frac{-6 \pm \sqrt{76}}{2}$
$=\frac{-6 \pm 2 \sqrt{19}}{2}$
and $\frac{-6-2 \sqrt{19}}{2}=-3+\sqrt{19}$ and $-3-\sqrt{19}$
Here a = 1, b = 6 and c = – 10
Then $x =-\frac{b \pm \sqrt{b}^2-4 a c}{2 a}$
$=\frac{-(6) \pm \sqrt{(-6)^2-4(1)(-10)}}{2(1)}$
$=\frac{-6 \pm \sqrt{76}}{2}$
$=\frac{-6 \pm 2 \sqrt{19}}{2}$
and $\frac{-6-2 \sqrt{19}}{2}=-3+\sqrt{19}$ and $-3-\sqrt{19}$
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