Question
Solve equation by factorization : $2x^2 – 8x – 24 = 0$ when x∈I
✓
Answer
$2x^2 – 8x – 24 = 0$
$\Rightarrow x^2– 4x – 12 = 0 ...$(Dividing by $2)$
$\Rightarrow x^2 – 6x + 2x – 12 = 0$
$\Rightarrow x (x – 6) + 2 (x – 6) = 0$
$\Rightarrow (x – 6) (x + 2) = 0$
Either$ x – 6 = 0$, then, $x = 6$
or $x + 2 = 0$, then$ x = – 2$
Hence$ x = 6, – 2.$
$\Rightarrow x^2– 4x – 12 = 0 ...$(Dividing by $2)$
$\Rightarrow x^2 – 6x + 2x – 12 = 0$
$\Rightarrow x (x – 6) + 2 (x – 6) = 0$
$\Rightarrow (x – 6) (x + 2) = 0$
Either$ x – 6 = 0$, then, $x = 6$
or $x + 2 = 0$, then$ x = – 2$
Hence$ x = 6, – 2.$
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