Question
Solve equation by factorization : $2x^2 – 9x + 10 = 0$,when $x\in Q$

Answer

$ 2 x^2-9 x+10=0 $
$ \Rightarrow 2 x^2-4 x-5 x+10=0 $
$ \Rightarrow 2 x(x-2)-5(x-2)=0 $
$ \Rightarrow(x-2)(2 x-5)=0$
Either $x-2=0$,
then $x=2$,
or
$2 x-5=0 \text {, }$
then $2 x=5$
$\Rightarrow x =\frac{5}{2}$
When $x \in Q$ then $x=2, \frac{5}{2}$.

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