Question
Solve equation by factorization : $3x^2= x + 4$

Answer

$
\begin{aligned}
& 3 x^2=x+4 \\
& \Rightarrow 3 x^2-x-4=0 \\
& \Rightarrow 3 x^2-4 x+3 x-4=0 \\
& \Rightarrow x(3 x-4)+1(3 x-4)=0 \\
& \Rightarrow(3 x-4)(x+1)=0
\end{aligned}
$
Either $3 x-4=0$,
then $3 x =4$
$
\Rightarrow x =\frac{4}{3}
$
or
$
x+1=0 \text {, }
$
then $x=-1$
Hence $x=\frac{4}{3},-1$.

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