Question
Solve equation by factorization : x (2x + 1) = 6
✓
Answer
$
\begin{aligned}
& x(2 x+1)=6 \\
& 2 x^2+x-6=0 \\
& 2 x^2+4 x-3 x-6=0 \\
& \Rightarrow 2 x(x+2)-3(x+2)=0 \\
& \Rightarrow(x+2)(2 x-3)=0
\end{aligned}
$
Either $x+2=0$,
then $x=-2$
or
$
2 x-3=0 \text {, }
$
then $2 x=3$
$
\Rightarrow x =\frac{3}{2}
$
Hence $x=-2, \frac{3}{2}$.
\begin{aligned}
& x(2 x+1)=6 \\
& 2 x^2+x-6=0 \\
& 2 x^2+4 x-3 x-6=0 \\
& \Rightarrow 2 x(x+2)-3(x+2)=0 \\
& \Rightarrow(x+2)(2 x-3)=0
\end{aligned}
$
Either $x+2=0$,
then $x=-2$
or
$
2 x-3=0 \text {, }
$
then $2 x=3$
$
\Rightarrow x =\frac{3}{2}
$
Hence $x=-2, \frac{3}{2}$.
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