Question
Solve equation by factorization : $x^2 – (p + q)x + pq = 0$
✓
Answer
$x^2 – (p + q)x + pq = 0$
$x^2 - px - qx + pq = 0$
$x(x - p) -q)x - p) = 0$
$\Rightarrow (x - p) (x - q) = 0$
Either $x - p = 0,$
then $x = p$
or
$x - q = 0,$
then$ x = q$
Hence$ x = p, q.$
$x^2 - px - qx + pq = 0$
$x(x - p) -q)x - p) = 0$
$\Rightarrow (x - p) (x - q) = 0$
Either $x - p = 0,$
then $x = p$
or
$x - q = 0,$
then$ x = q$
Hence$ x = p, q.$
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