Question
Solve equation by factorization$\frac{x^2-5 x}{2}=0$

Answer

$
\begin{aligned}
& \frac{x^2-5 x}{2}=0 \\
& x^2-5 x=0 \\
& \Rightarrow x(x-5)=0
\end{aligned}
$
Either $x =0$ or $x -5=0$,
then $x=5$
Hence $x=0,5$.

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