Question
Solve equation using factorisation method $: 2\left(x^2-6\right)=3(x-4)$
✓
Answer
$2\left(x^2-6\right)=3(x-4)$
$\Rightarrow 2 x^2-12=3 x-12$
$ \Rightarrow 2 x^2-3 x=0 $
$ \Rightarrow x(2 x-3)=0$
Since $x=0$ or $2 x-3=0$
then $x =0$ or $x =\frac{3}{2}$
$\Rightarrow 2 x^2-12=3 x-12$
$ \Rightarrow 2 x^2-3 x=0 $
$ \Rightarrow x(2 x-3)=0$
Since $x=0$ or $2 x-3=0$
then $x =0$ or $x =\frac{3}{2}$
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