Question
Solve equation using formula : $256x^2 – 32x + 1 = 0$
✓
Answer
$
256 x^2-32 x+1=0
$
Here $a=256, b=-32, c=1$
$
\begin{aligned}
& D=b^2-4 a c \\
& =(-32)^2-4 \times 256 \times 1 \\
& =1024-1024 \\
& =0
\end{aligned}
$
$
\begin{aligned}
& \because x=\frac{-b \pm \sqrt{D}}{2 a} \\
& =\frac{-(-32) \pm \sqrt{0}}{2 \times 256} \\
& =\frac{32}{512} \\
& =\frac{1}{16} \\
& x_1=\frac{1}{16}, x_2=\frac{1}{16}
\end{aligned}
$
Hence $x=\frac{1}{16}, \frac{1}{16}$.
256 x^2-32 x+1=0
$
Here $a=256, b=-32, c=1$
$
\begin{aligned}
& D=b^2-4 a c \\
& =(-32)^2-4 \times 256 \times 1 \\
& =1024-1024 \\
& =0
\end{aligned}
$
$
\begin{aligned}
& \because x=\frac{-b \pm \sqrt{D}}{2 a} \\
& =\frac{-(-32) \pm \sqrt{0}}{2 \times 256} \\
& =\frac{32}{512} \\
& =\frac{1}{16} \\
& x_1=\frac{1}{16}, x_2=\frac{1}{16}
\end{aligned}
$
Hence $x=\frac{1}{16}, \frac{1}{16}$.
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